Functions As Maps

Go back to  'Functions'

Learn from the best math teachers and top your exams

  • Live one on one classroom and doubt clearing
  • Practice worksheets in and after class for conceptual clarity
  • Personalized curriculum to keep up with school

Maps are a convenient way to visualise functions, or more generally, the association between two sets. A map relates one set to another using some rule. For example, suppose the rule is, \(y = f(x) = {x^2},\;{\rm{Set\,A}} = \{ 1,\;2,\;3,\;4\} ,\;{\rm{Set\,B}} = \{ 1,\;4,\;9,\;16\} \)

We can show this as a map.

Mapping two functions

The elements in \({\text{set B}}\) are the images of the elements of \({\text{set A}}\) under the action of \(f.\)

\({\text{Set A}}\) would be called the domain of \(f\left\{ {{\text{the set of all input values}}}\right\},\)  and \({\text{set B}}\) the co-domain of

\(f\left\{ {{\text{the set in which the output values lie}}}\right\}.\) Here, the co-domain is the same as the range{precisely

 the set of all outputs}, but in general, range would be a subset of the co-domain

Range \( \subseteq \) co-domain.

For our purposes, co-domain is not of much significance. It is more of a matter of convenience to specify the co-domain.

Suppose I want to talk about \(f(x) = \sqrt {a - x}  + \sqrt {x - b} ,\,a > b > 0\) (the function we analysed earlier). Note that the domain is \([b,\,a].\) The output will obviously be real and positive (This much I can tell just by looking at the definition of \(f(x)\)).

Hence, I could specify the definition of \(f\) as

As we can see above, co-domain just tells us that all the outputs will lie in it. The exact set of outputs (the range) will lie in the co-domain, and will be its subset.

We know that the range for this \(f(x)\) is \([\sqrt {a - b} ,\sqrt {2(a - b)} ]\)

Therefore, I can also specify \(f\) as

In this definition, co-domain is the same as range. Note that co-domain can be at the most equal to range (not smaller).

The map in the figure above is an example of a one-one and onto map. Let us see what this means, and what are the various possible kinds of maps.


One-one implies that each element in the domain set is mapped to only one element in the co-domain set, that is, no two inputs map to the same output.

The one-one condition can be written mathematically as

\(f({x_1}) = f({x_2})\)  if and only if  \({x_1} = {x_2}\)

This, stated in words, says that two outputs from f can be equal if and only if the  corresponding inputs to f are equal.

If \(f({x_1}) = f({x_2})\) does not imply \({x_1} = {x_2}\), then the function is many-one. Therefore, given \(f,\) we can find whether its one-one or not by solving the equation \(f({x_1}) = f({x_2})\). If this equation yields \({x_1} = {x_2}\), then \(f\) is one-one else not. As an example, consider \(f(x)=x^2.\) Is this one-one, or many one?


\(f({x_1}) = f({x_2}) \qquad \Rightarrow \qquad x_1^2 = x_2^2\)

\(\begin{align}&\Rightarrow \qquad ({x_1} + {x_2})({x_1} - {x_2}) = 0\\& \Rightarrow \qquad {x_1} = {x_2}\,\,\,{\rm{or}}\,\,\,{x_1} = - {x_2} \end{align}\)

Hence  \(f({x_1}) = f({x_2})\)  does not uniquely imply  \({x_1} = {x_2}\)  (Because another case exists,  \({x_1} = -{x_2}\) )

For example  \(f(3) = f( - 3) = 9\) (One output for two different inputs). Hence \(f(x) = {x^2}\)  is many-one

On a graph, this implies that if we draw any horizontal line, and it intersects the graph at the most once, then it is one-one, else it is many-one.

Note: One-many or many-many maps also exist but they are not functions. A function implies that each element in the domain is associated with one and only one element in the co-domain

For the graph of a valid function, this implies that if we draw a vertical line, it should intersect the graph at the most once. Otherwise, it is not a function.


Look carefully at the three maps below. The first and the third are many-one, while the second is one-many.

Any other differences? For the first two maps, each element in the co-domain (\({\text{Set B}}\)) is ‘covered’, that is, associated with some element in the domain (\({\text{Set A.}}\)) For the third map, one element \((\{ f\})\) in the co-domain is ‘left out’ (is not associated with any element in the domain, or in other words, does not have a pre-image). The first two maps are onto while the third is into.

Stating formally, an onto map is a map in which the range (the set of all images of the elements of the domain) ‘covers’ the entire co-domain, that is, \({\bf{\text{Range}}}={\bf{\text{Co-domain}}}.\)

If \({\text{Range}}\subset{\text{Co-domain}}\) (like the third map above), then it is an into map.

An example will make all this more clear:

The range is the set of all non-negative numbers, as \({x^2} \ge 0.\) Hence, Range \( \subset \) Co-domain and the function is into. On the other hand, for

Range = Co-domain and the map is onto.

Download SOLVED Practice Questions of Functions As Maps for FREE
grade 11 | Questions Set 1
grade 11 | Answers Set 1
grade 11 | Questions Set 2
grade 11 | Answers Set 2