November 23, 2020
Reading Time: 2 minutes
Introduction
Are you ready to solve an intriguing puzzle on prime numbers?
Prime number puzzles help children not only gain a deeper insight into prime numbers concepts but also strengthen their critical thinking skills for the subject.
Keeping this in mind, we have designed a fun and engaging prime numbers puzzle that will help your child understand the logic for prime number and solving factor puzzles in a fun and engaging way.
Also read:
This one is called “How many Pennies?” Go ahead! Give this a try!

What is the Solution and Logic for prime numbers puzzle
Here is the solution the the prime number puzzle:
First, let’s assume that the poorest one has x number of pennies.
Now, assume that the next child has the number of pennies equal to xy (where y is an integer)
Next, the ratio of the number of pennies that the third child possesses to the number of pennies possessed by the first two must be integer.
A simple way of achieving this is to assume that the third child has xyz number of pennies (again, z is an integer).

This way, the ratios will be:
xyz:xy = z:1 (integer ratio because z is assumed to be an integer)
xyz:x = yz:1 (multiplication of two integers will yield another integer).
Applying the same logic throughout, we can assume the fortunes of other children to be:
4th Child: xyzm (m is an integer)
5th Child: xyzmn (n is an integer)
6th Child: xyzmno (o is an integer)
7th Child: xyzmnop (p is an integer)
The sum of all fortunes is 2,879.
Mathematically,
x + xy + xyz + xyzm + xyzmn + xyzmno + xyzmnop = 2879
Taking out x as common:
x (1 + y + yz + yzm + yzmn + yzmno + yzmnop) = 2879
Note that 2879 is a prime number – which means that it can be divided only by itself and 1.
In other words, 2879 has only two factors – 1 and 2879.
Therefore, x = 1 and 1 + y + yz + yzm + yzmn + yzmno + yzmnop = 2879
Thus,
y + yz + yzm + yzmn + yzmno + yzmnop = 2879-1
y + yz + yzm + yzmn + yzmno + yzmnop = 2878
Taking y out as common:
y (1 + z + zm + zmn + zmno + zmnop) = 2878 = (2)(1439)
Once again, 1439 is a prime number. Therefore, y = 2
Thus,
1 + z + zm + zmn + zmno + zmnop = 1439
z + zm + zmn + zmno + zmnop = 1438
z (1 + m + mn + mno + mnop) = 1438 = (2)(719)
719 is a prime number. Therefore, z = 2
Solving like this, we get:
m = 2, n = 2, o = 2
Finally,
o (1 + p) = 178
(2)(1 + p) = 178
1 + p = 89
p = 88
Thus, the different fortunes will be:
1st Child: 1 penny
2nd Child: 1×2 = 2 pennies
3rd Child: 1x2x2 = 4 pennies
4th Child: 1x2x2x2 = 8 pennies
5th Child: 1x2x2x2x2 = 16 pennies
6th Child: 1x2x2x2x2x2 = 32 pennies
7th Child: 1x2x2x2x2x2x88 = 2816 pennies
Conclusion
Were you able to solve the tricky maths puzzle?
Either way, hopefully, you enjoyed putting your mind to use for finding the logic for prime number puzzles.
Puzzles are a great way to learn mathematical concepts due to the fun-based learning they provide. It is much more fun to use real life cases or hypothetical situations based on mysterious elements to learn concepts like prime numbers or factoring.
So go ahead and try such prime numbers puzzle and get to solving factor puzzles more. You will definitely have a fun experience.
And better yet, won’t it be cool to ask such puzzles to your friends at school?
About Cuemath
Cuemath, a student-friendly mathematics platform, conducts regular Online Live Classes for academics and skill-development and their Mental Math App, on both iOS and Android, is a one-stop solution for kids to develop multiple skills. Know more about the Cuemath fee here, Cuemath Fee
Frequently Asked Questions (FAQs)
Which is the smallest odd prime number?
3 is the smallest odd prime number
External References
To read more articles related to puzzles visit: