Exercise 1.4 Number Systems NCERT Solutions Class 9

Chapter 1 Ex.1.4 Question 1

Visualize \(\begin{align} 3.765\end{align}\) on the number line, using successive magnification.

Solution

Video Solution

Steps:

(i) \(3.7\) lies between \(3 \) & \(4\). So we divide the portion between \(3 \) & \(4\). on the number line into \(10\) equal parts

\(3.76\) lies between \(3.7\) and \(3.8\). So, we divide the portion between \(3.7\) and \(3.8\) on the number line into \(10\) equal parts.

\(3.765\) lies between \(3.76\) and \(3.77\) and \(3.77\) .Dividing the line before we got

Chapter 1 Ex.1.4 Question 2

Visualize \(\begin{align}4 . \overline{26}\end{align}\) on the number line, up to \(4\) decimal places.

Solution

Video Solution

Steps:

\(\begin{align}4 . \overline{26}=4.2626\dots\end{align}\) 

(i) \(4.2\) lies between \(4\) &\( 5\). Observe the number line given below

(ii) \(4.26\) lies between \(4.2\) & \(4.3\), shown below on the number line.

(iii) \(4.262\) lies between \(4.26\) & \(4.27\) as shown below.

(iv) \(4.2626\) lies between \(4.262\) & \(4.263\) as shown below

Hence by the successive magnification method required number is obtained in the number line.