NCERT Solutions For Class 10 Maths Chapter 10 Exercise 10.1

Go back to  'Circles'

Question 1

How many tangents can a circle have?

Solution

Video Solution

What is Unknown?

Number of tangents a circle can have

Reasoning:

A tangent to a circle is a line that intersects the circle at only one point. On every point on the circle, one tangent can be drawn.

Steps:

As per the above reasoning, a circle can have infinitely many tangents.

Question 2

Fill in the blanks:

(i) A tangent to a circle intersects it in _________ point (s).

(ii) A line intersecting a circle in two points is called a ____________.

(iii) A circle can have _________ parallel tangents at the most.

(iv) The common point of a tangent to a circle and the circle is called _________ .

Solution

Video Solution

Steps:

(i) A tangent to a circle intersects it in       One         point (s).

Reasoning:

A tangent to a circle is a line that intersects the circle at only one point.

(ii) A line intersecting a circle in two points is called a    Secant   .

Reasoning:

Secant is a line that intersects the circle in two points.

(iii) A circle can have    Two     parallel tangents at the most.

Reasoning:

Tangent at any point of a circle is perpendicular to the radius through the point of contact. Extended radius is a diameter which has two end points and hence two tangents which are parallel to themselves and perpendicular to the diameter.

Center \(O,\) diameter \(AB,\text{ tangents}\, PQ, RS\) and, \({PQ}\; \| \;{RS}\)

\(A\) and \(B\) are called as point of contact.

(iv) The common point of a tangent to a circle and the circle is called    Point of contact     .

Reasoning:

A tangent to a circle is a line that intersects the circle at only one point and that point is called as point of contact.

 

Question 3

A tangent \(PQ\) at a point \(P\) of a circle of radius \(\text{5 cm}\) meets a line through the center \(O\) at a point \(Q\) so that \(OQ = \text{12 cm.}\) Length \(PQ\) is:

(A) \(\text{12 cm}\)       

(B) \(\text{13 cm}\)       

(C) \(\text{8.5 cm}\)      

(D) \(\sqrt{119} \,\rm{cm.}\)

Solution

Video Solution

What is Known?

Radius \(OP = \text{5 cm} \)

\(OQ = \text{12 cm}\)

What is Unknown?

Length of the tangent \(PQ\)

Reasoning:

\(\Delta {OPQ}\) is a right-angle triangle according to Theorem \(10.1 :\) The tangent at any point of a circle is perpendicular to the radius through the point of contact.

Steps:

By Pythagoras theorem

\[\begin{align} {OQ} ^ { 2 } & = {O P} ^ { 2 } + {P Q} ^ { 2 } \\ 12 ^ { 2 } & = 5 ^ { 2 } + {P Q} ^ { 2 } \\ 144 & = 25 + {P Q} ^ { 2 } \\ {P Q} ^ { 2 } & = 119 \\ {P Q} & = \sqrt { 119 } \rm {\;cm } \end{align}\]

The answer is option D.

Question 4

Draw a circle and two lines parallel to a given line such that one is a tangent and the other, a secant to the circle.

Solution

Video Solution

What is Known?

(i) To draw a circle

(ii) Draw one tangent and one secant to the circle parallel  to the given line.

What is Unknown?

To draw a circle as per known details.

Steps:

\(XY\) is the given line.

\(AB\) is the secant parallel to \(XY,\) \({AB}\parallel {XY}\)

\(AQ\) is the tangent parallel to \(XY,\) \({PQ}\parallel {XY}\)

 

Download SOLVED Practice Questions of NCERT Solutions For Class 10 Maths Chapter 10 Exercise 10.1 for FREE
Ncert Class 10 Exercise 10.1
Ncert Solutions For Class 10 Maths Chapter 10 Exercise 10.1
  
Download SOLVED Practice Questions of NCERT Solutions For Class 10 Maths Chapter 10 Exercise 10.1 for FREE
Ncert Class 10 Exercise 10.1
Ncert Solutions For Class 10 Maths Chapter 10 Exercise 10.1
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