# Excercise 4.1 Practical Geometry- NCERT Solutions Class 8

Practical Geometry

## Chapter 4 Ex.4.1 Question 1

Construct the following quadrilaterals.

(i) Quadrilateral \(ABCD.\)

\(AB = 4.5 \,\rm{cm}\)

\(BC = 5.5\,\rm{ cm}\)

\(CD = 4\,\rm{cm} \)

\(AD = 6\,\rm{cm} \)

\(AC = 7\,\rm{} cm\)

(ii) Quadrilateral \(JUMP\)

\(JU = 3.5\,\rm{cm} \)

\(UM = 4\,\rm{cm}\)

\(MP = 5\,\rm{cm}\)

\(PJ = 4.5\,\rm{cm}\)

\(PU = 6.5\,\rm{cm}\)

(iii) Parallelogram \(MORE\)

\(OR = 6\,\rm{cm}\)

\(RE = 4.5\,\rm{cm}\)

\(EO = 7.5\,\rm{cm}\)

(iv) Rhombus \(BEST\)

\(BE = 4.5\,\rm{cm}\)

\(ET = 6\,\rm{cm}\)

**Solution**

**Video Solution**

**What is the known?**

Measurements of a Quadrilateral

**What is unknown?**

Construction of a Quadrilateral

**Reasoning:**

As you are aware, we need five measurements to draw a quadrilateral (Page 58 of Grade 8 NCERT Book)

Based on the given information, the five given measurements are of \(4\) sides and one diagonal.When measurements of \(4\) sides and one diagonal of a quadrilateral is given, we can construct a quadrilateral (Page 58 of Grade 8 NCERT Book)

**Steps:**

Let us first draw a rough sketch of quadrilateral.

Construction of quadrilateral can be done in two parts. First construct triangle \(ABC\) and then triangle \(ACD.\) Let us find based on given measurements whether it is possible to construct the triangles.

In \(ABC,\;5.5+4.5>7\) and \(5.5-4.5<7\)

\(7+4.5>5\) and \(7-4.5<5.5\)

\(5.5+7>4.5\) and \(7-5.5<4.5\)

It is possible to draw triangle \(ABC.\)

In \(ACD\)

\(7+4>6\) and \(7-4<6\)

\(6+7>4\) and \(7-6<4\)

\(6+4>7\) and \(6-4<7\)

So construction of triangle \(ACD\) is also possible.

Let us construct the quadrilateral.

**Step 1:** Draw line segment \(\begin{align}{{AB}} = 4.5\text{ cm}{{.}}\end{align}\) With \(B\) as center and radius \(5.5\, \rm{cm}\) draw an arc. With \(A\) as center and radius \(7 \,\rm{cm}\) draw another arc cutting the former arc. \(C\) is the intersecting point of arcs. Join \(BC\) and \(AC.\)

**Step 2:** Based on rough diagram, it is easy to find that \(AC\) is the diagonal. Therefore, the fourth vertex \(D\) should be on the opposite to \(B\) with reference to \(AC\).

**Step 3:** With \(A\) as center and radius \(6\,\rm{cm}\) draw an arc on the opposite side of point \(B.\) With \(C\) as center and radius \(4\,\rm{cm}\) draw another arc cutting the former arc. \(D\) is the intersecting point of the arcs. Join \(AD\) and \(CD.\) \(ABCD\) is the required quadrilateral.

**Related Problems.**

Ex 4.1 (ii)

(iii) Parallelogram \(MORE\)

Using the concept opposite sides of parallelogram are parallel and equal, the five measurements can be found.

(iv) Rhombus \(BEST\)

\(BE = 4.5\,\rm{cm}\)

\(ET = 6\, \rm{cm}\)

All sides of a rhombus are equal and opposite sides are parallel, measurements of all sides can be found.