# Excercise 4.3 Practical Geometry- NCERT Solutions Class 8

Practical Geometry

## Question 1

Construct the following quadrilaterals.

(i) Quadrilateral \( MORE \)

\(MO = 6\,\rm{cm}\)

\(OR = 4.5\,\rm{cm}\)

\(\angle {M = 60 }^\circ\)

\(\angle {O = 105 }^\circ\)

\(\angle R = 105^\circ\)

(ii) Quadrilateral \( PLAN\)

\(PL=4\,\rm{cm}\)

\(LA=6.5\,\rm{cm}\)

\(\angle P=90^\circ\)

\(\angle A=110^\circ\)

\(\angle N=85^\circ\)

(iii) Parallelogram \(HEAR\)

\(HE = 5\,\rm{cm}\)

\(EA = 6\,\rm{cm} \)

\(\angle R = 85^\circ\)

(iv) Rectangle \(OKAY\)

\(OK=7\,\rm{cm}\)

\(KA=5\,\rm{cm}\)

### Solution

**Video Solution**

**What is known?**

Measurements of two sides and three angles

**What is unknown?**

Construction of a Quadrilateral

**Reasoning:**

As you are aware, we need five measurements to draw a quadrilateral .

The measurements of two adjacent sides and three angles

**Steps:**

Let us draw a rough diagram of the quadrilateral

Let us construct the quadrilateral

**Step 1:** Draw a line segment \(MO=6 \,\rm{cm}.\)

**Step 2: **With \(M\) as center draw angle of measure \(60^\circ.\)

**Step 3:** Draw \( 105^\circ\) from \(O.\)

**Step 4:** With \(O\) as center and radius \(4.5\,\rm{cm}\) draw an arc cutting the ray from \(O\) at \(R.\) \(OR = 4.5\,\rm{cm}\)

**Step 5:** Construct an angle of \(105^{\circ}\) from \(R\) as above. The ray from \(R\) meets the ray from \(M\) at a point. Mark the intersection point as \(E.\)

**Step 6:** \(MORE\) is the required quadrilateral.

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