# Ex.10.4 Q1 Practical Geometry Solution- NCERT Maths Class 7

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## Question

Construct \(ΔABC\), given \(m∠A = 60^\circ\), \(m∠B = 30^\circ \) and \(AB = 5.8\,\rm{ cm}\).

Video Solution

Practical Geometry

Ex 10.4 | Question 1

## Text Solution

**What is known?**

Length of side of a \(ΔABC\), \(AB = 5.8\,\rm{ cm}\) and \(∠A = 60^\circ\), \(∠B = 30^\circ \).

**To construct:**

A triangle \(ΔABC\), given \(∠A = 60^\circ\), \(∠B = 30^\circ \) and \(AB = 5.8\,\rm{ cm}\).

**Reasoning:**

To Construct a \(ΔABC\) such that \(∠A = 60^\circ, ∠B = 30^\circ\) and \(AB = 5.8 \,\rm{cm}\)., follow the steps given below.

**Steps:**

__Steps of construction:__

- Draw a line segment \(AB\) of length \(5.8\,\rm{ cm}.\)
- At \(A\), draw ray \(AY\) making \(60^\circ\) with \(AB\).
- At \(B\), draw ray \(BX\) making \(30^\circ\) with \(AB\).
- Rays \(BX\) and \(AY\) will intersect at point \(C\).

Triangle \(ABC\) is now completed.