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Ex.13.5 Q1 Surface Areas and Volumes Solution - NCERT Maths Class 9

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Question

A matchbox measures \(\rm 4 cm × 2.5 cm × 1.5 cm.\) What will be the volume of a packet containing 12 such boxes?

 Video Solution
Surface-Areas-And-Volumes
Ex exercise-13-5 | Question 1

Text Solution

Reasoning:

Volume of cuboid is base area \(\times\)height

Therefore,

Volume \(=\) length \(\times\) breadth \(\times\) height

Volume is the space occupied by the solid.

What is known?

The measurements \(l, b, h\) of a cuboid.

What is unknown?

Volume of the container containing \(12\) such boxes.

Steps:

length \((l) = 4\,\,\rm cm\)

breadth \((b) = 2.5\,\,\rm cm \)

height \((h) = 1.5\,\,\rm cm\) 

Volume of a cuboid

\[\begin{align}=l \times b \times h \end{align}\]

Volume of \(1\) matchbox

\[\begin{align} = 4 \times 2.5 \times 1.5 \end{align}\]

Volume of \(12\) such boxes

\[\begin{align} = 4 \times 2.5 \times 1.5 \times 12  = 180\,\,c{m^3}\end{align}\]

Answer:

Volume of a packet containing \(12\) such boxes

\(\begin{align} = 180\,\,\rm c{m^3} \end{align}\)