# Ex.13.5 Q1 Surface Areas and Volumes Solution - NCERT Maths Class 9

## Question

A matchbox measures \(\rm 4 cm × 2.5 cm × 1.5 cm.\) What will be the volume of a packet containing 12 such boxes?

## Text Solution

**Reasoning:**

Volume of cuboid is base area \(\times\)height

Therefore,

Volume \(=\) length \(\times\) breadth \(\times\) height

Volume is the space occupied by the solid.

**What is known?**

The measurements \(l, b, h\) of a cuboid.

**What is unknown?**

Volume of the container containing \(12\) such boxes.

**Steps:**

length \((l) = 4\,\,\rm cm\)

breadth \((b) = 2.5\,\,\rm cm \)

height \((h) = 1.5\,\,\rm cm\)

Volume of a cuboid

\[\begin{align}=l \times b \times h \end{align}\]

Volume of \(1\) matchbox

\[\begin{align} = 4 \times 2.5 \times 1.5 \end{align}\]

Volume of \(12\) such boxes

\[\begin{align} = 4 \times 2.5 \times 1.5 \times 12 = 180\,\,c{m^3}\end{align}\]

**Answer:**

Volume of a packet containing \(12\) such boxes

\(\begin{align} = 180\,\,\rm c{m^3} \end{align}\)