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Ex.15.3 Q1 Introduction to Graphs Solutions - NCERT Maths Class 8

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Question

Draw the graphs for the following tables of values, with suitable scales on the axes.

(a)  Cost of apples

Number of apples

\(1\)

\(2\)

\(3\)

\(4\)

\(5\)

Cost (in Rs)

\(5\)

\(10\)

\(15\)

\(20\)

\(25\)

(b) Distance travelled by a car

Time (in hours)

\(6 \,\text{am.}\)

\(7 \,\text{am.}\)

\(8 \,\text{am.}\)

\(9 \,\text{am.}\)

Distance (in km)

\(40\)

\(80\)

\(120\)

\(160\)

(i) How much distance did the car cover during the period \(7.30\;\rm{a.m.} \) to \(8\;\rm{a.m.} \)?

(ii) What was the time when the car had covered a distance of \(100 \;\rm{km}\) since its start?

(c) Interest on deposits for a year:

Deposit (in Rs)

\(1000\)

\(2000\)

\(3000\)

\(4000\)

\(5000\)

Simple interest (in Rs)

\(80\)

\(160\)

\(240\)

\(320\)

\(400\)

(i) Does the graph pass through the origin?

(ii) Use the graph to find the interest on \(\rm{Rs} \;2500\) for a year:

(iii) To get an interest of \(\rm{Rs} \;280\) per year, how much money should be deposited?

 Video Solution
Introduction To Graphs
Ex 15.3 | Question 1

Text Solution

Reasoning:

a) Considering ‘Number of apples’ on horizontal axis and ‘Cost (in \(\rm{Rs}\))’ on vertical axis starting from origin i.e. (\(0,0\)) and find the value of ‘Cost’ on vertical axis according to the given value of ‘Number of apples’ on the horizontal axis value or vice versa.

 b)  Considering ‘Time (in hours)’ on horizontal axis and ‘Distance (in \(\rm{km}\))’ on vertical axis starting from origin i.e. (\(0,0\)) and find the value of ‘Distance’ on vertical axis according to the given value of ‘Time’ on the horizontal axis value orvice versa.

c) Considering ‘Deposit (in \(\rm{Rs}\))’ on horizontal axis and ‘Simple interest (in \(\rm{Rs}\))’ on vertical axis starting from origin i.e. (\(0,0\)) and find the value of ‘Simple interest’ on vertical axis according to the given value of ‘Deposit’ on the horizontal axis value orvice versa.

Steps:

(a) Taking a suitable scale :

For x-axis, \(2\) unit \(= 1\) apple and for y-axis, \(2\) unit \(= \rm{Rs} \;5.\)

We can mark the number of apples on x-axis and the cost of apples on y-axis.

A graph of the given data is as follows.

(b) Taking a suitable scale

For x-axis, \(4\) units \(= 1\) hour and for y-axis,\( 2\) units \(= 20 \,\rm{km}\),

We can represent the time on x-axis and the distance covered by the car on y- axis.

A graph of the given data is as follows.

(i) During the period \(7:30 \,\rm{a.m.}\) to \(8 \rm{a.m.}\), the car covered a distance of \(20 \,\rm{km.}\)

(ii) The car covered a distance of \(100 \,\rm{km}\) at \(7:30 \,\rm{a.m.}\) since its start.

(c) Taking a suitable scale,

For x-axis, \(2\) unit = \(\rm{Rs}\, 1000\) and for y-axis, \(2\) unit = \(\rm{Rs}\, 50\)

We can represent the deposit on x-axis and the interest earned on that deposit on y-axis. A graph of the given data is obtained as follows.

From the graph, the following points can be observed.

(i) Yes. The graph passes through the origin.

(ii) The interest earned in a year on a deposit of \(\rm{Rs}\, 2500\) is \(\rm{Rs}\, 200.\)

(iii) To get an interest of \(\rm{Rs}\,280\) per year, \(\rm{Rs} \,3500\) should be deposited.

  
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