Ex.2.3 Q1 fractions-and-decimals Solutions-Ncert Maths Class 7

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Question

Find:

(i) \(\begin{align} \frac{1}{4}\rm\,of\end{align} \)           (a) \(\begin{align} \frac{1}{4}\end{align} \)     (b) \(\begin{align} \frac{3}{5}\end{align} \)     (c) \(\begin{align} \frac{4}{3}\end{align} \)

(ii) \(\begin{align} \frac{1}{7}\rm \,of \end{align} \)          (a) \(\begin{align} \frac{2}{9}\end{align} \)     (b) \(\begin{align} \frac{6}{5}\end{align} \)     (c) \(\begin{align} \frac{3}{10}\end{align} \)

Text Solution

What is known?

Fractions

What is unknown?

Product of the given fractions.

Reasoning:

Find the product by multiplying numerator with numerator and denominator with denominator.

Steps:

\(\begin{align} \text{ (i) }\left( \text{a} \right)\text{ }\frac{1}{4}\text{ of }\frac{1}{4}&=\frac{1}{4}\times \frac{1}{4}\\&=\frac{1}{16}\\ \\ \text{ }\,\,\,\,\,\,\,\,\text{(b) }\frac{1}{4}\text{ of }\frac{3}{5}&=\frac{1}{4}\times \frac{3}{5}\\&=\frac{3}{20} \\\\ \text{ (c) }\frac{1}{4}\text{ of }\frac{4}{3}&=\frac{1}{4}\times \frac{4}{3}\\&=\frac{4}{12}\\&=\frac{1}{3} \\\end{align}\)

 

\(\begin{align} \text{ (ii) (a) }\frac{1}{7}\text{ of }\frac{2}{9}&=\frac{1}{7}\times \frac{2}{9}\\&=\frac{1\times 2}{7\times 9}\\&=\frac{2}{63} \\\\ \text{ }\,\text{    (b) }\frac{1}{7}\text{ of }\frac{6}{5}&=\frac{1}{7}\times \frac{6}{5}\\&=\frac{1\times 6}{7\times 5}\\&=\frac{6}{35} \\\\ \text{ (c) }\frac{1}{7}\text{ of }\frac{3}{10}&=\frac{1}{7}\times \frac{6}{5}\\&=\frac{1\times 3}{7\times 10}\\&=\frac{3}{70} \\\end{align}\)

 

  
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