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# Ex.2.5 Q1 Linear Equations in One Variable Solution - NCERT Maths Class 8

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## Question

Solve the linear equation \begin{align}\frac{x}{2} - \frac{1}{5} = \frac{x}{3} + \frac{1}{4}\end{align}

Video Solution
Linear Equations
Ex 2.5 | Question 1

## Text Solution

What is known?

Equation

What is unknown?

Value of the variable

Reasoning:

Multiple both sides by the L.C.M of the denominators to get rid of fractional number. Now transpose variables to one side and constant to another side.

Steps:

\begin{align}\frac{x}{2} - \frac{1}{5} = \frac{x}{3} + \frac{1}{4}\end{align}

LCM of the denominators, $$2, 3, 4,$$ and $$5$$, is $$60.$$

Multiplying both sides by $$60,$$ we obtain

\begin{align}60\left( {\frac{x}{2} - \frac{1}{5}} \right) = 60\left( {\frac{x}{3} + \frac{1}{4}} \right)\end{align}

Opening the  brackets, we get,
\begin{align}30x - 12 &= 20x + 15 \\30x - 20x &= 15 + 12\\10x &= 27\quad \quad \\\,\,\,\,\,x &= \frac{{27}}{{10}}\end{align}

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