# Ex.2.6 Q1 Linear Equations in One Variable Solutions-Ncert Maths Class 8

Go back to  'Ex.2.6'

## Question

Solve: \begin{align}\frac{{8x - 3}}{{3x}} = 2\end{align}

## Text Solution

What is known?

Equation

What is unknown?

Value of the variable

Reasoning:

Multiple both sides by the L.C.M of the denominators to get rid of fractional number. Now transpose variables to one side and constant to another side.

Steps:

\begin{align}\frac{{8x - 3}}{{3x}} = 2\end{align}

On multiplying both sides by $$3x$$, we obtain

\begin{align}8x - 3 = 6x \\8x - 6x = 3 \\\,\,\,\,\,\,\,\,\,\,2x = 3 \\\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{3}{2} \\\end{align}

Learn from the best math teachers and top your exams

• Live one on one classroom and doubt clearing
• Practice worksheets in and after class for conceptual clarity
• Personalized curriculum to keep up with school