# Ex.6.5 Q1 Triangles Solution - NCERT Maths Class 10

## Question

Sides of triangles are given below. Determine which of them are right triangles.

In case of a right triangle, write the length of its hypotenuse.

(i)  $$7 \;\rm{cm}, 24 \;\rm{cm}, 25\; \rm{cm}$$

(ii)  $$3\; \rm{cm}, 8 \;\rm{cm}, 6 \;\rm{cm}$$

(iii)  $$50\; \rm{cm}, 80 \;\rm{cm}, 100 \;\rm{cm}$$

(iv)  $$13\; \rm{cm}, 12 \;\rm{cm}, 5 \;\rm{cm}$$

Video Solution
Triangles
Ex 6.5 | Question 1

## Text Solution

Reasoning:

As we know,in a triangle, the square of one side is equal to the sum of the squares of the other two sides,then the angle opposite the first side is a right angle.

Steps:

(i) $${{(25)}^{2}} =625$$

\begin{align} {{7}^{2}}+{{24}^{2}}&=49+576 \\&=625 \\ \therefore \,\,\,\,{{(25)}^{2}}&={{7}^{2}}+{{24}^{2}} \\ \end{align}

Length of hypotenuse $$=$$ $$25\;\rm{cm}$$

(ii) $${{8}^{2}} =64$$

\begin{align} {{3}^{2}}+{{6}^{2}}&=9+36 \\ &=45 \\ {{8}^{2}}&\ne {{3}^{2}}+{{6}^{2}} \\ \end{align}

(iii) $${{(100)}^{2}}=1000$$

\begin{align} {{50}^{2}}+{{80}^{2}}&=2500+6400 \\ &=8900 \\ {{(100)}^{2}}&\ne {{50}^{2}}+{{80}^{2}} \\ \end{align}

(iv) $${{\left( 13 \right)}^{2}}=169$$

\begin{align} {{12}^{2}}+{{5}^{2}}&=144+25 \\ &=169 \\ \end{align}

$$\therefore{{(13)}^{2}}={{12}^{2}}+{{5}^{2}}$$

Length of hypotenuse $$=$$ $$13\;\rm{cm}$$

$$\Rightarrow$$ (i) and (iv) are right triangle.

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