Ex.7.5 Q1 Triangles Solution - NCERT Maths Class 9
\( ABC\) is a triangle. Locate a point in the interior of \(ΔABC\) which is equidistant from all the vertices of \(ΔABC.\)
Circumcentre of a triangle is always equidistant from all the vertices of that triangle.
Circumcentre is the point where perpendicular bisectors of all the sides of the triangle meet together.
In \(\Delta ABC\), we can find the circumcentre by drawing the perpendicular bisectors of sides \(AB, BC,\) and \(CA\) of this triangle. \(O\) is the point where these bisectors are meeting together. Therefore, \(O\) is the point which is equidistant from all the vertices of \(\Delta ABC\).