# Ex.11.3 Q11 Perimeter and Area - NCERT Maths Class 7

## Question

A circle of radius \(2\rm\, cm\) is cut out from a square piece of an aluminum sheet of side \(6\rm\, cm\). What is the area of the left-over aluminum sheet? (Take \(π = 3.14\))

## Text Solution

**What is known?**

A square piece of an aluminum sheet of side \(6\rm\, cm\) from which a circle of radius \(2\rm\, cm\) is cut out.

**What is unknown?**

The area of the left-over aluminum sheet.

**Reasoning:**

First, find the area of the piece of the aluminum sheet then subtract the area of the circle from it and you can get the area of the left -over aluminum sheet.

**Steps:**

Side of square piece of aluminum sheet \(=\) \(6\rm\, cm\) and radius of circle \(=\) \(2\rm\, cm\)

Area of aluminium sheet left \(=\) Total area of square aluminum sheet \(-\) Area of circle

\[\begin{align} &= {\rm{Side}} \times {\rm{Side}} - \pi {r^2}\\ &= 6 \times 6 - 3.14 \times 2 \times 2\\ &= 36 - 12.56\\ &= 23.44\;\rm c{m^2}\end{align}\]

Therefore, the area of aluminum sheet left is \(23.44 \rm\,cm^2.\)