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# EX.2.1 Q12 Linear Equations in One Variable Solutions - NCERT Maths Class 8

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## Question

Solve the equation:

\begin{align}\frac{x}{3}\,\, + \,\,1\,\, = \,\,\frac{7}{{15}}\end{align}

Video Solution
Linear Equations
Ex 2.1 | Question 12

## Text Solution

What is known?

Equations

What is unknown?

Value of the variable

Reasoning:

In an equation values of left-hand side (LHS) and right-hand side (RHS) are equal. The two sides of the equation are balanced. We perform mathematical operations so that the balance is not disturbed.

Steps:

Transposing $$1$$ to RHS, we get ,

\begin{align}\frac{x}{3}\,\,\, &= \,\,\frac{7}{{15}}\,\, - \,\,1\\\frac{x}{3}\,\, &= \,\,\frac{{7 - 15}}{{15}}\\\frac{x}{3}\,\, &= \,\,\frac{{ - 8}}{{15}}\end{align}

Now multiplying both sides by $$3$$, we get

\begin{align}\frac{x}{3} \times 3\,\, &= \,\, - \frac{8}{{15}} \times 3\\x\,\, &= \,\,\frac{{ - 8}}{5}\end{align}

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