# Ex.14.3 Q14 Factorization - NCERT Maths Class 8

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## Question

**Q14.** Find and correct the errors in the statement:

\[{(y - 3)^2} = {y^2} - 9\]

## Text Solution

**What is known?**

Incorrect mathematical statement.

**What is unknown?**

Correct mathematical statement.

**Reasoning:**

Use identity \({(a - b)^2} = {a^2} - 2ab + {b^2}\)

**Steps:**

\[\begin{align}{L.H.S. = {(y - 3)}^2} &= {{(y)}^2} - 2(y)(3) + {{(3)}^2} \quad {\left[ {{\text {Using identity}}\;\;{{(a - b)}^2} = {a^2} - 2ab + {b^2}} \right]}\\&= {y^2} - 6y + 9\\L.H.S. &\ne R.H.S.\end{align}\]

The correct statement is \({(y - 3)^2} = {y^2} - 6y + 9\)