# Ex.15.1 Q14 Probability Solution - NCERT Maths Class 10

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## Question

One card is drawn from a well-shuffled deck of $$52$$ cards. Find the probability of getting

(i) a king of red colour

(ii) a face card

(iii) a red face card

(iv) the jack of hearts

(vi) the queen of diamonds

Video Solution
Probability
Ex 15.1 | Question 14

## Text Solution

What is known?

One card is drawn from a well-shuffled deck of $$52$$ cards.

What is unknown?

The probability of getting

(i) a king of red colour

(ii) a face card

(iii) a red face card

(iv) the jack of hearts

(vi) the queen of diamonds

This question can be solved easily by using the formula

Reasoning:

Probability of an event

$=\frac{\begin{bmatrix} \text { Number of}\\ \text{ possible outcomes }\end{bmatrix} }{ \begin{bmatrix}\text { Total no of} \\ \text{favorable outcomes} \end{bmatrix} }$

Steps:

Total number of cards from a well-shuffled deck = $$52$$

No of spade cards $$=13$$

No of heart cards $$=13$$

No of diamond cards$$=13$$

No of club cards$$=13$$

Total number of kings $$= 4$$

Total number of queens$$= 4$$

Total number of jack cards $$= 4$$

No of face cards $$= 12$$

(i) Probability of getting a king of red colour

\begin{align} \text{ }&=\frac{\text{Number of red colour king}}{\text{Total no of outcomes}} \\ &=\frac{2}{52}=\frac{1}{26} \end{align}

(ii) Probability of getting a face card

\begin{align} \text{ } & =\frac{\text{ Number of face cards }}{\text{ Total no of outcomes }} \\ {} & =\frac{12}{52}=\frac{3}{13} \\\end{align}

(iii) Probability of getting a red face card

\begin{align}&=\frac{\text{ Number of red face cards}}{\text{Total no of outcomes}} \\ &=\frac{6}{52}=\frac{3}{26} \\ \end{align}

(iv) Probability of getting the jack of hearts

\begin{align}&{ = \frac{{{\text{ Number of jack of hearts}}}}{{{\text{total no of outcomes}}}}}\\{}&{= \frac{1}{{52}}} \end{align}

(v) Probability of getting a spade card

\begin{align}&=\frac{\text{ Number of spade cards}}{\text{Total no of outcomes}} \\&=\frac{13}{52}\\&=\frac{1}{4} \\\end{align}

(vi) Probability of getting the queen of diamonds

\begin{align} &= \frac{ \begin{Bmatrix} \text{ Number of} \\ \text{possible} \\ \text{ outcomes} \end{Bmatrix}}{\begin{Bmatrix}\text { Total no of} \\ \text{favorable} \\ \text{outcomes} \end{Bmatrix}} \\ & =\frac{1}{52} \\ \end{align}

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