Ex.15.1 Q19 Probability Solution - NCERT Maths Class 10

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Question

A child has a die whose six faces show the letters as given below:

\(A\) \(B\) \(C\) \(D\) \(E\) \(A\)

The die is thrown once. What is the probability of getting

(i) \(\rm A?\) 

(ii) \(\rm D?\)

 Video Solution
Probability
Ex 15.1 | Question 19

Text Solution

 

What is known?

A die has six faces which show the letters as shown in the diagram and it is thrown once.

\(A\) \(B\) \(C\) \(D\) \(E\) \(A\)

What is unknown?

The probability of getting (i) \(\rm A?\) (ii) \(\rm D?\)

Steps:

Total number of outcomes = \(6\)

(i) Probability of getting \(\rm A\)

\[\begin{align}& =\frac{\text{Number of possible outcomes}}{\text{No of favourable outcomes}} \\& =\frac{2}{6} \\\end{align}\]

(ii) Probability of getting \(\rm D\)

\[\begin{align}& =\frac{\text{Number of possible outcomes}}{\text{No of favourable outcomes}} \\ & =\frac{1}{6} \\\end{align}\]

The probability of getting \(\rm A\) and \(\rm D\) is \(\begin{align}\frac{2}{6}\text{ and }\frac{1}{6}\end{align}\)