# Ex.15.1 Q19 Probability Solution - NCERT Maths Class 10

## Question

A child has a die whose six faces show the letters as given below:

\(A\) | \(B\) | \(C\) | \(D\) | \(E\) | \(A\) |

The die is thrown once. What is the probability of getting

(i) \(\rm A?\)

(ii) \(\rm D?\)

## Text Solution

**What is known?**

A die has six faces which show the letters as shown in the diagram and it is thrown once.

\(A\) | \(B\) | \(C\) | \(D\) | \(E\) | \(A\) |

**What is unknown?**

The probability of getting (i) \(\rm A?\) (ii) \(\rm D?\)

**Steps:**

Total number of outcomes = \(6\)

(i) Probability of getting \(\rm A\)

\[\begin{align}& =\frac{\text{Number of possible outcomes}}{\text{No of favourable outcomes}} \\& =\frac{2}{6} \\\end{align}\]

(ii) Probability of getting \(\rm D\)

\[\begin{align}& =\frac{\text{Number of possible outcomes}}{\text{No of favourable outcomes}} \\ & =\frac{1}{6} \\\end{align}\]

The probability of getting \(\rm A\) and \(\rm D\) is \(\begin{align}\frac{2}{6}\text{ and }\frac{1}{6}\end{align}\)