Ex.10.2 Q2 Practical Geometry Solution- NCERT Maths Class 7

Go back to  'Ex.10.2'

Question

 Construct an equilateral triangle of side \(5.5\,\rm{cm} \).

Text Solution

 

What is known?

Lengths of sides of an equilateral triangle are \(5.5\,\rm{cm}\) each.

To construct:

An equilateral triangle of side \(5.5\,\rm{cm} \).

Reasoning:

To construct an equilateral triangle of side \(5.5\,\rm{cm} \). Follow the steps given below

Steps:

Steps of construction :

  1. Draw a line segment \(BC\) of length \(5.5\,\rm{cm} \).
  2. From \(B\), point \(A\) is at a distance of \(5.5\,\rm{cm} \).So, with \(B\) as centre, draw an arc of radius \(5.5\,\rm{cm} \) (Now \(A\) will be somewhere on this arc. Our job is to find where exactly \(A\) is).
  3. From \(C\), point \(A\) is at a distance of \(5.5\,\rm{cm} \).So, with \(C\) as centre, draw an arc of radius \(5.5\,\rm{cm} \) (Now \(A\) will be somewhere on this arc, we have to fix it).
  4. \(A\) has to be on both the arcs drawn. So, it is the point of intersection of arcs. Mark the point of intersection of arcs as \(A\) join \(AB \) and \(AC\).

Thus, \(ABC\) is the required triangle.

  
Learn from the best math teachers and top your exams

  • Live one on one classroom and doubt clearing
  • Practice worksheets in and after class for conceptual clarity
  • Personalized curriculum to keep up with school