# Ex.10.3 Q2 Practical Geometry Solution- NCERT Maths Class 7

Go back to 'Ex.10.3'

## Question

Construct an isosceles triangle in which the lengths of each of its equal sides is \(6.5\,\rm{ cm}\) and the angle between them is \(110^\circ\)

Video Solution

Practical Geometry

Ex 10.3 | Question 2

## Text Solution

**What is known?**

Lengths of each of its equal sides is \(6.5\,\rm{ cm}\) and the angle between them is \(110^\circ.\)

**To construct:**

An isosceles triangle in which the lengths of each of its equal sides is \(6.5\,\rm{ cm}\) and the angle between them is \(110^\circ.\)

**Reasoning:**

To construct an isosceles triangle in which the lengths of each of its equal sides is \(6.5\,\rm{ cm}\) and the angle between them is \(110^\circ,\) follow the steps given below.

**Steps:**

__Steps of construction :__

- Draw a line segment \(QR\) of length \(6.5\,\rm{cm}.\)
- At \(Q,\) draw \(QX\) making an angle of \(110^\circ\) with \(QR.\)
- With \(Q\) as centre, draw an arc of radius \(6.5\,\rm{cm}.\) It cuts \(QX\) at the point \(P.\)
- Join \(PR\). Triangle \(PQR\) is the required isosceles triangle.