# Ex.11.2 Q2 Constructions Solution - NCERT Maths Class 9

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## Question

Construct a triangle \(ABC\) in which \({BC}=8\;\mathrm{cm}, \angle B=\;45^{\circ}\) and \(AB-AC=3.5\;\rm{cm}.\)

Video Solution

Constructions

Ex 11.2 | Question 2

## Text Solution

**Steps of Construction:**

(i) Draw base \( BC = 8\;\rm{cm}\) and at point \(B\) make an angle of using \(45^{\circ}\) a protractor.

(ii) With \(B\) as centre and radius \( BD = 3.5\;\rm{cm} \), draw an arc to intersect ray \(BX\) at \(D\).

(iii) Join \(DC\)

(iv) With \(D\) and \(C\) as the centre and radius greater than half of \(DC\). Draw arcs above and below the line to intersect ray \(BX\) at \(A\).

(v) Join \(AC\).\(ABC\) is the required triangle.