# Ex.11.3 Q2 Mensuration Solution - NCERT Maths Class 8

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## Question

A suitcase with measures $$80\,\rm{ cm} × 48\, \rm{cm} × 24\,\rm{ cm}$$ is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width $$96\,\rm{cm}$$ is required to cover $$100$$ such suitcases?

Video Solution
Mensuration
Ex 11.3 | Question 2

## Text Solution

What is Known?

Number of suitcases to be covered and dimensions of each suitcase.

What is unknown?

Required length of tarpaulin cloth cover suitcase

Reasoning:

Find the surface area of a suitcase.

Steps:

Let the length of the tarpaulin cloth $$= l \,\rm{cm}$$

Total surface of the suitcase

\begin{align} &= 2[(80\! \times\! 48) \!+\! (48\! \times\! 24) \!+\!(24 \!\times \!80)]\,{\rm{cm}^2}\\&= 2[3840 + 1152 + 1920]\,{\rm{c}}{{\rm{m}}^2}\\ &= 13824 \,\rm{m^2} \end{align}

Total surface area of $$100$$ suitcases

\begin{align} &= 100 \times 13824\,{{\rm{m}}^2}\\&= 1382400\,\,{\rm{cm}^2}\end{align}

Required Tarpaulin cloth

$= {\rm{Length\! \times\! Breadth}}$

$$1382400\,{\rm{c}}{{\rm{m}}^2} = l \times 96\,{\rm{cm}}$$

\begin{align}l& = \frac{{1382400}}{{96}}\,\,{\rm{cm}}\\&= 14400\,\,{\rm{cm}}\\l& = 144\,\rm{m}\end{align}

Thus, $$144\;\rm{ m}$$ of tarpaulin cloth is required to cover $$100$$ suitcases.

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