Ex.11.3 Q2 Mensuration Solution - NCERT Maths Class 8

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A suitcase with measures \(80\,\rm{ cm} × 48\, \rm{cm} × 24\,\rm{ cm}\) is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width \(96\,\rm{cm}\) is required to cover \(100\) such suitcases?

 Video Solution
Ex 11.3 | Question 2

Text Solution

What is Known?

Number of suitcases to be covered and dimensions of each suitcase.

What is unknown?

Required length of tarpaulin cloth cover suitcase


Find the surface area of a suitcase.


Let the length of the tarpaulin cloth \(= l \,\rm{cm}\)

Total surface of the suitcase

\[\begin{align} &= 2[(80\! \times\! 48) \!+\! (48\! \times\! 24) \!+\!(24 \!\times \!80)]\,{\rm{cm}^2}\\&= 2[3840 + 1152 + 1920]\,{\rm{c}}{{\rm{m}}^2}\\ &= 13824 \,\rm{m^2} \end{align}\]

Total surface area of \(100\) suitcases

\[\begin{align} &= 100 \times 13824\,{{\rm{m}}^2}\\&= 1382400\,\,{\rm{cm}^2}\end{align}\]

Required Tarpaulin cloth

\[= {\rm{Length\! \times\! Breadth}}\]

\(1382400\,{\rm{c}}{{\rm{m}}^2} = l \times 96\,{\rm{cm}}\) 

\[\begin{align}l& = \frac{{1382400}}{{96}}\,\,{\rm{cm}}\\&= 14400\,\,{\rm{cm}}\\l& = 144\,\rm{m}\end{align}\]

Thus, \(144\;\rm{ m}\) of tarpaulin cloth is required to cover \(100\) suitcases.

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