# Ex.13.1 Q2 Surface Areas and Volumes - NCERT Maths Class 9

## Question

The length, breadth and height of a room are $$5 \,\rm{m}, 4 \,\rm{m},$$ and $$3\,\rm{ m}$$ respectively. Find the cost of white washing the walls of the room and ceiling at the rate of \begin{align} \text{Rs 7.50 per }\rm{m^2}? \end{align}

Video Solution
Surface Areas And Volumes
Ex 13.1 | Question 2

## Text Solution

What is known:

Medium

What is unknown:

The lenght, breadth and height of a room are $$5m$$, $$4m$$, and $$3m$$ respectively.

Reasoning:

Since the four walls and ceiling are to be whitewashed. So, it has $$5$$ faces only, excluding the base.

Hence, area of the room to be whitewashed can be obtained by adding area of the ceiling to the lateral surface area of the cuboidal room.

Lateral surface area of cuboid $$=2(l+b)h$$ The cost of white washing the walls of the room and ceiling will be equal to area of the room to be whitewashed multiplied by rate of the whitewashing.

Steps:

\begin{align} \\\text{length} &= 5\,\rm{m} \\\text{breadth} &= \rm{4\,m} \\\text{height} &= \rm{3 \,\,m} \end{align}

Surface are of $$5$$ faces $$=$$ Area of the $$4$$ walls and ceiling $$=$$ $$lb+2(l+b)h$$

\begin{align}&=(5m\!\times\!4m)\!+\!2\!\times\!(5m\!+\!4m)\!\times\!3m\\ &= 20m^2+2\times9m\times3m \\&=20m^2+54m^2 \\&=74m^2\end{align}

The cost of white washing the walls of the room and ceiling = $$Rate\times area$$

\begin{align}&=₹ 7.50/m^2\times 74m^2\\ &= ₹\,555\end{align}

Answer:

Cost of white washing the walls of the room and the ceiling $$= Rs. 555$$

Learn from the best math teachers and top your exams

• Live one on one classroom and doubt clearing
• Practice worksheets in and after class for conceptual clarity
• Personalized curriculum to keep up with school