# Ex.3.2 Q2 Data Handling - NCERT Maths Class 7

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## Question

The runs scored in a cricket match by $$11$$ players are as follows: -
$$6, 15, 120, 50, 100,80, 10,15,\\ 8, 10, 15$$

Find the mean, median and mode of the data. Are they same?

Video Solution
Data Handling
Ex 3.2 | Question 2

## Text Solution

What is known?

Runs scored in a cricket match by $$11$$ Players

What is unknown?

The mean, median and mode of the data

Reasoning: \begin{align}\text{Mean}=\frac{\text{Sum of all scores}}{\text{Total no}\text{. of players}}\end{align}

Mode $$=$$ Mode is the observation that occurs highest number of times

Median$$=$$Median is the middle observation

Steps:

Total number of players $$= 11$$

Scores of players $$= 6, 15, 120, 50, 100,80, 10,15, 8, \\ \quad10, 15$$

\begin{align}{\rm{Mean}}& = \frac{{{\text{Sum of all scores}}}}{{{\text{Total no}}.{\text{of players}}}} \\ &= \frac{{\left[ \begin{array}{l}{\rm{6}} + {\rm{8}} + {\rm{1}}0 + {\rm{15}} + \\{\rm{15}} + {\rm{15}} + {\rm{5}}0 + {\rm{8}}0 + \\{\rm{1}}00 + {\rm{12}}0 \\\end{array} \right]}}{{11}} \\ &= \frac{{{\rm{429}}}}{{11}} \\ &= 39 \\\end{align}

Thus, mean $$= 39.$$

Arranging the scores into ascending order, we get
$$6, 8, 10,10, 15, 15,15, 50, 80, \\ 100, 120$$

Mode is the observation that occurs highest number of times

Here, $$15$$ occurs $$3$$ times

$$∴$$  Mode $$=15.$$

Median is the middle observation

$$∴$$  Median $$= 15$$ (6th observation)

Thus, Mean $$=$$ $$39$$ , Mode $$=$$ $$15$$ and median $$=$$ $$15$$

No, the mean, mode and median are not same.

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