# Ex.3.3 Q2 Coordinate Geometry Solution - NCERT Maths Class 9

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## Question

Plot the points (\(x, y\)) given in the following table on the plane, choosing suitable units of distance on the axes.

\({x}\) | \(-2\) | \(-1\) | \(0\) | \(1\) | \(3\) |

\(y\) | \(8\) | \(7\) | \(-1.25\) | \(3\) | \(-1\) |

Video Solution

Coordinate Geometry

Ex 3.3 | Question 2

## Text Solution

**Steps:**

Given,

\(x\) | \(-2\) | \(-1\) | \(0\) | \(1\) | \(3\) |

\(y\) | \(8\) | \(7\) | \(-1.25\) | \(3\) | \(-1\) |

Draw \(x-\)axis and \(y-\)axis as the co-ordinate axes and mark their point of intersection \(O\) as the Origin (\(0, 0\)).

In order to plot the points given in the table provided above,

- Let us mark the first point as \(A\,(–2, 8)\)
- Take \(2\) units on the negative \(x-\)axis and then \(8\) units on positive \(y-\)axis.

- Let us mark the second point as \(B\,(–1, 7)\)
- Take \(-1\) unit on negative \(x-\)axis and then \(7\) units on positive \(y-\)axis.

- Let us mark the third point as \(C\,(0, –1.25),\)
- Take \(1.25\) units below
*\(x-\)axis*on negative \(y-\)axis.

- Take \(1.25\) units below
- Let us mark the fourth point as \(D\,(1, 3)\)
- Take \(1\) unit on positive \(x-\)axis and then \(3\) units on positive \(y-\)axis.

- Let us mark the fifth point as \(E\,(3, –1)\)
- Take \(3\) units on positive \(x-\)axis and then move \(-1\) unit on negative \(x-\)axis.