Ex.3.3 Q2 Coordinate Geometry Solution - NCERT Maths Class 9

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Question

Plot the points (\(x, y\)) given in the following table on the plane, choosing suitable units of distance on the axes.

\({x}\) \(-2\) \(-1\) \(0\) \(1\) \(3\)
\(y\) \(8\) \(7\) \(-1.25\) \(3\) \(-1\)

 Video Solution
Coordinate Geometry
Ex 3.3 | Question 2

Text Solution

Steps:

Given,

\(x\) \(-2\) \(-1\) \(0\) \(1\) \(3\)
\(y\) \(8\) \(7\) \(-1.25\) \(3\) \(-1\)

Draw \(x-\)axis and \(y-\)axis as the co-ordinate axes and mark their point of intersection \(O\) as the Origin (\(0, 0\)).

In order to plot the points given in the table provided above,

  • Let us mark the first point as \(A\,(–2, 8)\)
    • Take \(2\) units on the negative \(x-\)axis and then \(8\) units on positive \(y-\)axis.
  • Let us mark the second point as \(B\,(–1, 7)\)
    • Take \(-1\) unit on negative \(x-\)axis and then \(7\) units on positive \(y-\)axis.
  • Let us mark the third point as \(C\,(0, –1.25),\)
    • Take \(1.25\) units below \(x-\)axis on negative \(y-\)axis.
  • Let us mark the fourth point as \(D\,(1, 3)\)
    • Take \(1\) unit on positive \(x-\)axis and then \(3\) units on positive \(y-\)axis.
  • Let us mark the fifth point as \(E\,(3, –1)\)
    • Take \(3\) units on positive \(x-\)axis and then move \(-1\) unit on negative \(x-\)axis.

  
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