Ex.1.4 Q3 Integers Solution - NCERT Maths Class 7

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Question

Fill in the blanks: –

a) \(\begin{align}369 \div\underline{\qquad\qquad}    = 369 \end{align}\) b) \(\begin{align}(–75) \div\underline{\qquad\qquad}   = –1 \end{align}\)
c) \(\begin{align}(–206) \div\underline{\qquad\qquad}   = 1 \end{align}\) d) \(\begin{align}(–87)\div\underline{\qquad\qquad}  = 87 \end{align}\)
e) \(\begin{align}\underline{\qquad\qquad} \div1 = –87\end{align}\) f) \(\begin{align}\underline{\qquad\qquad} \div48 = –1\end{align}\)
g) \(\begin{align}20\div \underline{\qquad\qquad}  = –2\end{align}\) h) \(\begin{align}\underline{\qquad\qquad} \div (4) = –3\end{align}\)

 

Text Solution

   

Steps:

a) \(\begin{align}369 \div\underline{\qquad1\qquad}   = 369 \end{align}\) b) \(\begin{align}(–75) \div\underline{\qquad75\qquad}  = –1 \end{align}\)
c) \(\begin{align}(–206) \div\underline{\qquad(–206)\qquad}  = 1 \end{align}\) d) \(\begin{align}(–87)\div\underline{\qquad(-1)\qquad} = 87 \end{align}\)
e) \(\begin{align}\underline{\qquad(-87)\qquad} \div1 = –87\end{align}\) f) \(\begin{align}\underline{\qquad(-48)\qquad} \div48 = –1\end{align}\)
g) \(\begin{align}20\div \underline{\qquad(-10)\qquad} = –2\end{align}\) h) \(\begin{align}\underline{\qquad(-12)\qquad} \div (4) = –3\end{align}\)

 

  
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