Ex.1.4 Q3 Integers Solution - NCERT Maths Class 7

Go back to  'Ex.1.4'

Question

Fill in the blanks: –

a)  \(\begin{align}369 \div\underline{\qquad\qquad} = 369 \end{align}\)

b)  \(\begin{align}(–75) \div\underline{\qquad\qquad} = –1 \end{align}\)

c)  \(\begin{align}(–206) \div\underline{\qquad\qquad} = 1 \end{align}\)

d)  \(\begin{align}(–87)\div\underline{\qquad\qquad} = 87 \end{align}\)

e)  \(\begin{align}\underline{\qquad\qquad} \div1 = –87\end{align}\)

f)  \(\begin{align}\underline{\qquad\qquad} \div48 = –1\end{align}\)

g)  \(\begin{align}20\div \underline{\qquad\qquad} = –2\end{align}\)

h)  \(\begin{align}\underline{\qquad\qquad} \div (4) = –3\end{align}\)

 

 Video Solution
Integers
Ex 1.4 | Question 3

Text Solution

Steps:

a)  \(\begin{align}369 \div\underline{\qquad1\qquad} = 369 \end{align}\)

b)  \(\begin{align}(–75) \div\underline{\qquad75\qquad} = –1 \end{align}\)

c)  \(\begin{align}(–206) \div\underline{\qquad(–206)\qquad} = 1 \end{align}\)

d)  \(\begin{align}(–87)\div\underline{\qquad(-1)\qquad} = 87 \end{align}\)

e)  \(\begin{align}\underline{\qquad(-87)\qquad} \div1 = –87\end{align}\)

f)  \(\begin{align}\underline{\qquad(-48)\qquad} \div48 = –1\end{align}\)

g)  \(\begin{align}20\div \underline{\qquad(-10)\qquad} = –2\end{align}\)

h)  \(\begin{align}\underline{\qquad(-12)\qquad} \div (4) = –3\end{align}\)

  
Learn from the best math teachers and top your exams

  • Live one on one classroom and doubt clearing
  • Practice worksheets in and after class for conceptual clarity
  • Personalized curriculum to keep up with school