Ex.10.3 Q3 Practical Geometry Solution- NCERT Maths Class 7

Go back to  'Ex.10.3'

Question

Construct \(\Delta ABC\) with \(BC = 7.5\,\rm{ cm}\), \(AC = 5\,\rm{ cm}\) and \(m∠C = 60^\circ\).

Text Solution

What is known?

Lengths of sides of a triangle are \(BC = 7.5\,\rm{ cm}\), \(AC = 5\,\rm{ cm}\) and \(∠C = 60^\circ\).

To construct:

A triangle \(\Delta ABC\)  with \(BC = 7.5\,\rm{ cm}\), \(AC = 5\,\rm{ cm}\) and \(∠C = 60^\circ\).

Reasoning:

To construct a triangle \(ΔABC\) with \(BC = 7.5\,{\rm{ cm}}, AC = 5\,\rm{ cm}\) and \(∠C = 60^\circ\), follow the steps given below.

Steps:

Steps of construction :

  1. Draw a line segment \(BC\) of length \(7.5\,\rm{cm}.\)
  2. At \(C\), draw \(CX\) making \(60^\circ\) with \(BC\).
  3. With \(C\) as centre, draw an arc of radius \(5\,\rm{cm}.\) It cuts \(CX\) at the point \(A\).
  4. Join \(AB.\)

Triangle \(ABC\) is the required triangle.

  
Learn from the best math teachers and top your exams

  • Live one on one classroom and doubt clearing
  • Practice worksheets in and after class for conceptual clarity
  • Personalized curriculum to keep up with school