# Ex.11.2 Q3 Constructions Solution - NCERT Maths Class 9

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## Question

Construct a triangle \(PQR\) in which \(QR=6\;\mathrm{cm}, Q=\angle 60^{\circ}\) and \(PR-PQ= 2\;\rm{cm}.\)

Video Solution

Constructions

Ex 11.2 | Question 3

## Text Solution

**Steps of Construction:**

(i) Draw line \(QR =6\;\rm{cm}\) . Make an angle of \(60^{\circ}\) at a point \(Q\) using a protractor and extend it below line \(QR\).

(ii) With \(Q\) as center and radius as \(2\;\rm{cm}\), draw an arc to intersect the ray \(QX\) at \(Z\)

(iii) Join \(RZ\)

(iv) With \(Z\) and \(R\) as centres and radius greater than half of \(ZR\), draw arcs on either side to intersect each other.

(v) Join the intersecting points and extend it to meet the ray \(QY\) at \(P\).

(vi) Join \(P\) and \(R\) .\(PQR\) is the required triangle.