Ex.2.4 Q3 fractions-and-decimals Solutions-Ncert Maths Class 7

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Question

 Find:

(i) \(\begin{align} \frac{7}{3} \div 2\end{align} \)

(ii) \(\begin{align} \frac{4}{9} \div 5 \end{align} \)

(iii) \(\begin{align} \frac{6}{{13}} \div 7\end{align} \)

(iv) \(\begin{align} 4\frac{1}{3} \div 3\end{align} \)

(v) \(\begin{align} 3\frac{1}{2} \div 4\end{align} \)

(vi) \(\begin{align} 4\frac{3}{7} \div 7\end{align} \)

Text Solution

What is known?

Expression.

What is unknown?

Value of the expression.

Reasoning:

To divide fractions take the reciprocal of the divisor and multiply it with dividend.

Steps:

(i) \(\begin{align} \frac{7}{3} \div 2\end{align} \)

\[\begin{align}&= \frac{7}{3} \times \frac{1}{2}\\&= \frac{7}{6}({\text{ improper fraction }})\end{align}\]

Converting into mixed fraction, we get \(\begin{align} = 1\frac{1}{6} \end{align}\)

(ii) \(\begin{align} \frac{4}{9} \div 5 \end{align} \)

\[\begin{align}&= \frac{4}{9} \times \frac{1}{5}\\&= \frac{4}{{45}}\end{align}\]

(iii) \(\begin{align} \frac{6}{{13}} \div 7\end{align} \)

\[\begin{align}& = \frac{6}{{13}} \times \frac{1}{7}\\ &= \frac{6}{{91}}\end{align}\]

(iv) \(\begin{align} 4\frac{1}{3} \div 3\end{align} \)

\[\begin{align}&= \frac{{13}}{3} \times \frac{1}{3}\\&= \frac{{13}}{9}({\text{ Improper fraction }})
\end{align}\]

Converting into mixed fraction, we get \(\begin{align} = 1\frac{4}{9} \end{align}\)

(v) \(\begin{align} 3\frac{1}{2} \div 4\end{align} \)

\[\begin{align}&= \frac{7}{2} \times \frac{1}{4}\\&= \frac{7}{8}\end{align}\]

(vi) \(\begin{align} 4\frac{3}{7} \div 7\end{align} \)

\[\begin{align}&= 4\frac{3}{7} \times \frac{1}{7}\\&= \frac{{31}}{7} \times \frac{1}{7}\\&= \frac{{31}}{{49}}\end{align}\]

  
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