Ex.2.6 Q3 Linear Equations in One Variable Solutions-Ncert Maths Class 8

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 Solve: \(\begin{align}\frac{z}{{z + 15}} = \frac{4}{9}\end{align}\)

 Video Solution
Linear Equations
Ex 2.6 | Question 3

Text Solution

What is known?


What is unknown?

Value of the variable


Multiple both sides by the L.C.M of the denominators to get rid of fractional number. Now transpose variables to one side and constant to another side.


On multiplying both sides by\(\begin{align} {\text{ 9(}}z{\text{ + 15), }} \hfill \\ \end{align} \)we obtain

\[\begin{align}9z& = 4\left( {{\rm{z + 15}}} \right)\\9z &= 4z + 60\\9z - 4z &= 60\\\,\,\,\,\,\,\,5z &= 60\\\,\,\,\,\,\,\,\,\,z &= 12\end{align}\]