Ex.2.6 Q3 Linear Equations in One Variable Solutions-Ncert Maths Class 8

Go back to  'Ex.2.6'

Question

 Solve: \(\begin{align}\frac{z}{{z + 15}} = \frac{4}{9}\end{align}\)

 Video Solution
Linear Equations
Ex 2.6 | Question 3

Text Solution

What is known?

Equation

What is unknown?

Value of the variable

Reasoning:

Multiple both sides by the L.C.M of the denominators to get rid of fractional number. Now transpose variables to one side and constant to another side.

Steps:

On multiplying both sides by\(\begin{align} {\text{ 9(}}z{\text{ + 15), }} \hfill \\ \end{align} \)we obtain

\[\begin{align}9z& = 4\left( {{\rm{z + 15}}} \right)\\9z &= 4z + 60\\9z - 4z &= 60\\\,\,\,\,\,\,\,5z &= 60\\\,\,\,\,\,\,\,\,\,z &= 12\end{align}\]