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# Ex.4.2 Q3 Simple-Equations Solution - NCERT Maths Class 7

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## Question

Give the steps you will use to separate the variable and then solve the equation:

(a) \begin{align}3n-2 = 46\end{align}

(b) \begin{align}5m + 7 = 17\end{align}

(c) \begin{align}\frac{{20p}}{3} = 40\end{align}

(d) \begin{align}\frac{{3p}}{{10}} = 6\end{align}

Video Solution
Simple Equations
Ex 4.2 | Question 3

## Text Solution

What is Known?

Equations

What is unknown?

The first step we use to separate the variable in order to solve the equations.

Reasoning:

First try to reduce the equation by adding, subtracting, multiplying or dividing both sides of the equation by the same number to get the value of variable.

Steps:

(a) $$3n-2 = 46$$

Adding $$2$$ to both sides of the equation, we get

\begin{align}3n-2 + 2 &= 46 + 2\\3n &= 48\end{align}

Dividing both the sides by $$3$$ we get,

\begin{align}\frac{{3n}}{3} = \frac{{48}}{3}\\n = 16\end{align}

(b) $$5m + 7 = 17$$

Subtracting $$7$$ from both sides of the equation, we get

\begin{align}5m + 7 - 7 &= 17 - 7\\5m& = 10\end{align}

Dividing both the sides by $$5$$ we get,

\begin{align}\frac{{5m}}{5} &= \frac{{10}}{5}\\m &= 2\end{align}

(c) \begin{align}\frac{{20p}}{3} = 40\end{align}

Multiplying both the sides by $$3$$ we get,

\begin{align}\frac{{20p}}{3} \times 3 &= 40 \times 3\\20p &= 120\end{align}

Dividing both the sides by $$20$$ we get,

\begin{align}\frac{{20p}}{{20}} &= \frac{{120}}{{20}}\\p &= 6\end{align}

(d) \begin{align}\frac{{3p}}{{10}} = 6\end{align}

Multiplying both the sides by $$10$$ we get,

\begin{align}\frac{{3p}}{{10}} \times 10 &= 6 \times 10\\3p &= 60\end{align}

Dividing both the sides by $$20$$ we get,

\begin{align}\frac{{3p}}{3} &= \frac{{60}}{3}\\p &= 20\end{align}

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