# Ex.6.4 Q3 Squares and Square Roots - NCERT Maths Class 8

## Question

Find the square root of the following decimal numbers.

(i) \(2.56\)

(ii) \(7.29\)

(iii) \(51.84\)

(iv) \(42.25\)

(v) \(31.36\)

## Text Solution

**What is known?**

Perfect squares in decimal form

**What is unknown?**

Square root by using division method

**Reasoning:**

To find the square root of decimal numbers put bars on the integral part of the number and place bars on the decimal part on every pair of digits starting with the first decimal place.

**Steps**:

(i)

Square root of \(2.56\) is calculated as:-

\[\sqrt {2.56}= 1.6\]

(ii)

Square root of \(7.29\) is calculated as

\[\sqrt {7.29}= 2.7\]

(iii)

Square root of \(51.84\) is calculated as

\[\sqrt {51.84}= 7.2\]

(iv)

Square root of \(42.25\) is calculated as follows

\[\sqrt {42.25}= 6.25\]

(v)

Square root of \(31.36 \) is calculated as follows

\[\sqrt {31.36}= 5.6\]