# Ex.9.3 Q3 Algebraic Expressions and Identities - NCERT Maths Class 8

Go back to  'Ex.9.3'

## Question

Find the product.

(i) \begin{align}\left( {{a^2}} \right) \times \left( {2{a^{22}}} \right) \times \left( {4{a^{26}}} \right) \end{align}

(ii) \begin{align}\left( {\frac{2}{3}xy} \right) \times \left( {\frac{{ - 9}}{{10}}{x^2}{y^2}} \right) \end{align}

(iii) \begin{align}\left( { - \frac{{10}}{3}p{q^3}} \right) \times \left( {\frac{6}{5}{p^3}q} \right) \end{align}

(iv) \begin{align} x \times {x^{2}} \times {x^3} \times {x^4} \end{align}

Video Solution
Algebraic Expressions & Identities
Ex 9.3 | Question 3

## Text Solution

What is known?

Expressions

What is unknown?

Simplification

Steps:

(i)

\begin{align} &\left( {{a^2}} \right) \times \left( {2{a^{22}}} \right) \times \left( {4{a^{26}}} \right) \\&= 2 \times 4 \times {a^2} \times {a^{22}} \times {a^{26}} \\&= 8{a^{50}}\end{align}

(ii)

\begin{align} &\left( {\frac{2}{3}xy} \right) \times \left( {\frac{{ - 9}}{{10}}{x^2}{y^2}} \right) \\&= \!\! \left( {\frac{\not{2}}{3}} \right) \! \! \times \!\! \left( {\frac{{ - 9}}{{\not{\!\!10^5}}}} \right) \! \times \! x \times \! y \! \times {x^2} \! \times \! {y^2} \\&= \frac{{ - 3}}{5}{x^3}{y^3}\end{align}

(iii)

\begin{align} & \left( \frac{-10}{3}p{{q}^{3}} \right)\times \left( \frac{6}{5}{{p}^{3}}q \right)\\&=\left(\frac{-1{{{\not\!0}}^{2}}}{3} \right)\times \left( \frac{6}{{\not\!5}} \right)\times p{{q}^{3}}\times{{p}^{3}}q\\&=-4{{p}^{4}}{{q}^{4}}\end{align}

(iv)

$x \times {x^2} \times {x^3} \times {x^4} = {x^{10}}$

Learn from the best math teachers and top your exams

• Live one on one classroom and doubt clearing
• Practice worksheets in and after class for conceptual clarity
• Personalized curriculum to keep up with school