Ex.9.3 Q3 Algebraic Expressions and Identities - NCERT Maths Class 8

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Question

Find the product.

(i) \(\begin{align}\left( {{a^2}} \right) \times \left( {2{a^{22}}} \right) \times \left( {4{a^{26}}} \right) \end{align}\)

(ii) \(\begin{align}\left( {\frac{2}{3}xy} \right) \times \left( {\frac{{ - 9}}{{10}}{x^2}{y^2}} \right) \end{align}\)

(iii) \(\begin{align}\left( { - \frac{{10}}{3}p{q^3}} \right) \times \left( {\frac{6}{5}{p^3}q} \right) \end{align}\)

(iv) \(\begin{align} x \times {x^{2}} \times {x^3} \times {x^4} \end{align}\)

 Video Solution
Algebraic Expressions & Identities
Ex 9.3 | Question 3

Text Solution

What is known?

Expressions

What is unknown?

Simplification

Steps:

(i)

\[\begin{align} &\left( {{a^2}} \right) \times \left( {2{a^{22}}} \right) \times \left( {4{a^{26}}} \right) \\&= 2 \times 4 \times {a^2} \times {a^{22}} \times {a^{26}} \\&= 8{a^{50}}\end{align}\]

(ii)

\[\begin{align} &\left( {\frac{2}{3}xy} \right) \times \left( {\frac{{ - 9}}{{10}}{x^2}{y^2}} \right) \\&= \!\! \left( {\frac{\not{2}}{3}} \right) \! \! \times \!\!  \left( {\frac{{ - 9}}{{\not{\!\!10^5}}}} \right) \! \times  \! x \times \! y \! \times {x^2} \! \times \! {y^2} \\&= \frac{{ - 3}}{5}{x^3}{y^3}\end{align}\]

(iii)

\[\begin{align} & \left( \frac{-10}{3}p{{q}^{3}} \right)\times \left( \frac{6}{5}{{p}^{3}}q \right)\\&=\left(\frac{-1{{{\not\!0}}^{2}}}{3} \right)\times \left( \frac{6}{{\not\!5}} \right)\times p{{q}^{3}}\times{{p}^{3}}q\\&=-4{{p}^{4}}{{q}^{4}}\end{align}\]

(iv)

\[x \times {x^2} \times {x^3} \times {x^4} = {x^{10}}\]

  
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