# Ex.1.2 Q4 Real Numbers Solution - NCERT Maths Class 10

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## Question

Given that HCF $$(306, 657) = 9$$, find LCM $$(306, 657)$$.

Video Solution
Real Numbers
Ex 1.2 | Question 4

## Text Solution

What is known?

HCF of two numbers $$(306, 657) = 9$$

What is unknown?

LCM of the given numbers

Reasoning:

We know that LCM $$\times$$ HCF $$=$$ product of two given integers

We have the given numbers as $$306$$ and $$657$$ and we can find the product of $$306$$ and $$657$$. The HCF of this two numbers is $$9$$. Put the values in the above property and find the value of unknown i.e. HCF.

Steps:

Given, HCF $$(306, 657) = 9.$$

We have to find,

LCM $$(306, 657) = ?$$

We know that

LCM$$\times$$ HCF $$=$$ Product of two numbers

\begin{align}\rm{LCM}\times\, 9 &= 306\, \times \,657\\\rm{LCM}&= {\frac{{306\, \times \,657}}{9}}\\\rm{LCM}&= 34\, \times \,657\\\rm{LCM}&= 22338 \end{align}

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