# Ex.1.2 Q4 Real Numbers Solution - NCERT Maths Class 10

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## Question

Given that HCF \((306, 657) = 9\), find LCM \((306, 657)\).

Video Solution

Real Numbers

Ex 1.2 | Question 4

## Text Solution

**What is known?**

HCF of two numbers \((306, 657) = 9\)

**What is unknown?**

LCM of the given numbers

**Reasoning:**

We know that LCM \(\times\) HCF \( =\)** **product of two given integers

We have the given numbers as \(306\) and \(657\) and we can find the product of \(306\) and \(657\). The HCF of this two numbers is \(9\). Put the values in the above property and find the value of unknown i.e. HCF.

**Steps:**

Given, HCF \((306, 657) = 9.\)

We have to find,

LCM \((306, 657) = ?\)

We know that

\[\begin{align}\rm{LCM}\times \rm{HCF}&= \text{Product of two numbers}\\\rm{LCM}\times\, 9 &= 306\, \times \,657\\\rm{LCM}&= {\frac{{306\, \times \,657}}{9}}\\\rm{LCM}&= 34\, \times \,657\\\rm{LCM}&= 22338 \end{align}\]