# Ex 2.2 Q4 Fractions-and-Decimals-Solutions NCERT Maths Class 7

## Question

Shade:

(i) \(\begin{align}\frac{1}{2}\end{align}\) of the circles in box (a)

(ii) \(\begin{align}\frac{2}{3}\end{align}\) of the triangles in box (b)

(iii) \(\begin{align}\frac{3}{5}\end{align}\) of the squares in box (c)

## Text Solution

**What is known?**

Fraction of the figure to be shaded and unshaded figure.

**What is unknown?**

Shaded figure according to given fraction.

**Reasoning: **

First multiple the fraction by number of parts of given figure that’s how we will get what number of parts need to be shade.

**Steps:**

(i) Total number of circles in box \((a) = 12\)

\(\begin{align}\frac{1}{2}\text{ of circles}&=\frac{1}{2} \times 12 \\&= 6\, \text{circles}\end{align}\)

So, \(6\) circles should be shaded

(ii) Total number of triangles in box \((b) = 9\)

\(\begin{align}\frac{2}{3} \text{ of triangles} &=\frac{2}{3} \times 9 \\&= 6 \,\text{triangles}\end{align}\)

So, \(6\) triangles should be shaded.

iii) Total number of squares in box \((c) = 15 \)

\(\begin{align}\frac{3}{5} \,{\rm of }\,\times 15\, \text{squares} &= \frac{3}{5} \times 15 \\&= 3 \times 3 \\&= 9 \text{ squares}\end{align}\)

So, \(9\) squares should be shaded