Ex 2.2 Q4 Fractions-and-Decimals-Solutions NCERT Maths Class 7

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(i) \(\begin{align}\frac{1}{2}\end{align}\) of the circles in box (a)

(ii) \(\begin{align}\frac{2}{3}\end{align}\) of the triangles in box (b)

(iii) \(\begin{align}\frac{3}{5}\end{align}\) of the squares in box (c)


 Video Solution
Fractions And Decimals
Ex 2.2 | Question 4

Text Solution

What is known?

Fraction of the figure to be shaded and unshaded figure.

What is unknown?

Shaded figure according to given fraction.


First multiple the fraction by number of parts of given figure that’s how we will get what number of parts need to be shade.


 (i) Total number of circles in box \((a) = 12\)

\(\begin{align}\frac{1}{2}\text{ of circles}&=\frac{1}{2} \times 12 \\&= 6\,  \text{circles}\end{align}\)

So, \(6\) circles should be shaded

(ii) Total number of triangles in box \((b) = 9\) 

\(\begin{align}\frac{2}{3} \text{ of triangles} &=\frac{2}{3} \times 9 \\&= 6 \,\text{triangles}\end{align}\)

So, \(6\) triangles should be shaded.

iii) Total number of squares in box \((c) = 15 \)

\(\begin{align}\frac{3}{5} \,{\rm of }\,\times 15\, \text{squares} &= \frac{3}{5} \times 15 \\&= 3 \times 3 \\&= 9 \text{ squares}\end{align}\)

So, \(9\) squares should be shaded

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