Ex.2.3 Q4 Polynomials Solution - NCERT Maths Class 10

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On dividing \(x^{3} -3 x^{2}+x +2\) by a polynomial \(g(x),\) the quotient and remainder were \(x – 2\) and \(–2x + 4,\) respectively. Find \(g(x).\)

 Video Solution
Ex 2.3 | Question 4

Text Solution

What is unknown?

Divisor \(g(x)\) of a polynomial \(p(x).\)


This question is straight forward, you can solve it by using division algorithm

Dividend \(=\) Divisor \(\times\) Quotient \(+\) Remainder

Put the given values in the above equation and simplify it, get the value of \(g(x).\)


Dividend \(=\) Divisor \(\times\) Quotient \(+\) Remainder

\[\begin{align}x^{3}-3 x^{2}+x+2&=g(x) \times x-2+(-2 x+4)\\\left(x^{3}-3 x^{2}+x+2\right)-(-2 x+4)&=g(x) \times x-2\\\left(x^{3}-3 x^{2}+x+2 x+2-4\right)&=g(x) \times x-2\\\left(x^{3}-3 x^{2}+3 x-2\right)&=g(x) \times x-2 \end{align}\]

Therefore, \(g\left( x \right) = {x^2} - x + 1\)

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