# Ex.2.6 Q4 Linear Equations in One Variable Solutions-Ncert Maths Class 8

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## Question

Solve:\begin{align}\frac{{3y + 4}}{{2 - 6y}} = \frac{{ - 2}}{5}\end{align}

Video Solution
Linear Equations
Ex 2.6 | Question 4

## Text Solution

What is known?

Equation

What is unknown?

Value of the variable

Reasoning:

Multiple both sides by the L.C.M of the denominators to get rid of fractional number. Now transpose variables to one side and constant to another side.

Steps:

On multiplying both sides by $$5(2-6 y),$$ we obtain

\begin{align} 5\left( 3\text{ }y+4 \right)&=-2\left( 2-6\text{ }y \right) \\15y+20&=-4+12\text{ }y \\15y-12y&=-4-20 \\3\,y&=-24 \\y &=-8\end{align}

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