# Ex.3.1 Q4 Data Handling - NCERT Maths Class 7

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## Question

A cricketer scores the following runs in eight innings:

\(58, 76, 40, 35, 46, 45, 0, 100\)

Find the mean score.

Video Solution

Data Handling

Ex 3.1 | Question 4

## Text Solution

**What is known?**

Runs in eight innings.

**What is unknown?**

Mean Score

**Reasoning:**

**\(\begin{align}\text{Mean of score}\!=\!\frac{\text{Sum of all runs}} {\text{Number of innings }}\end{align}\)**

**Steps:**

Total number of innings = \(8\)

Scores of cricketer in \(8\) innings

\[\begin{align} = 58,76,40,35,46,45,0,100\end{align}\]

Mean of score

\[\begin{align} &= \frac{{\left[ \begin{array}{l}58 + 76 + 40 + 35 +\\ 46 + 45 + 0 + 100\end{array} \right]}}{8}\\ &= \frac{{400}}{8}\\ &= 50\end{align}\]

Thus, the mean score of a cricketer in \(8\) innings is \(50.\)