# Ex.5.2 Q4 Data Handling Solutions - NCERT Maths Class 8

Go back to  'Ex.5.3'

## Question

Numbers $$1$$ to $$10$$ are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it.

What is the probability of:

(i)  getting a number $$6?$$

(ii)  getting a number less than $$6?$$

(iii) getting a number greater than $$6?$$

(iv)  getting a number less than $$6?$$

(v) getting a $$1-$$digit number?

Video Solution
Data Handling
Ex 5.3 | Question 4

## Text Solution

What is known?

Numbers $$1$$ to $$10$$ are written on ten separate slips (one number on one slip), kept in a box and mixed well

What is unknown?

(i) Probability of getting a number $$6$$

(ii) Probability of getting a number less than $$6$$

(iii) Probability of getting a number greater than $$6$$

(iv) Probability of getting a number less than $$6$$

(v) Probability of getting a $$1-$$digit number

Reasoning:

Probability\begin{align} = \frac{{{\text{Number of favourable outcomes}}}}{{{\text{Total number of outcomes}}}}\end{align}

Steps:

(i) Outcome of getting a number $$6$$ from ten separate slips is $$1$$. Therefore, probability of getting a number \begin{align}6 = \frac{1}{{10}}\end{align}

(ii) Numbers less than $$6$$ are $$1, 2, 3, 4$$ and $$5$$. So, there are $$5$$ outcomes. Therefore, probability of getting a number less than

\begin{align} 6 = \frac{5}{{10}} = \frac{1}{2} \end{align}

(iii) Number greater than 6 are $$7, 8, 9, 10.$$ So there are $$4$$ possible outcomes. Therefore, probability of getting a number greater than

\begin{align} 6 = \frac{4}{{10}} = \frac{2}{5} \end{align}

(iv) One-digit numbers are

$$1, 2, 3, 4, 5, 6, 7, 8, 9$$ out of ten.

Therefore, probability of getting a $$1$$-digit number

\begin{align} = \frac{9}{{10}} \end{align}

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