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Ex.11.2 Q5 Constructions Solution - NCERT Maths Class 9

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Construct a right triangle whose base is \(12\;\rm{cm}\)  and sum of its hypotenuse and other side is \(18\;\rm{cm}\)

 Video Solution
Ex 11.2 | Question 5

Text Solution

Steps of Construction:

(i) Draw the base \(BC=12\;\rm{cm} \).

(ii) At the point \(B\), make an angle \(CBX=90^\circ\) using a protractor.

(iii) Cut a line segment \(BD=18\;\rm{cm} \) from the ray \(BX\).

(iv) Join \(DC\)

(v) With \(D\) and \(C\) as the centres and radius greater than half of \(DC\) draw arcs on either side of the line to intersect each other. Join the intersecting points and extend the perpendicular bisector to meet \(BD\) at \(A\).

(vi) Join \(A\) and \(C\)\(ABC\) is the required right-angled triangle

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