# Ex.11.2 Q5 Constructions Solution - NCERT Maths Class 9

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## Question

Construct a right triangle whose base is \(12\;\rm{cm}\) and sum of its hypotenuse and other side is \(18\;\rm{cm}\)

Video Solution

Constructions

Ex 11.2 | Question 5

## Text Solution

**Steps of Construction:**

(i) Draw the base \(BC=12\;\rm{cm} \).

(ii) At the point \(B\), make an angle \(CBX=90^\circ\) using a protractor.

(iii) Cut a line segment \(BD=18\;\rm{cm} \) from the ray \(BX\).

(iv) Join \(DC\)

(v) With \(D\) and \(C\) as the centres and radius greater than half of \(DC\) draw arcs on either side of the line to intersect each other. Join the intersecting points and extend the perpendicular bisector to meet \(BD\) at \(A\).

(vi) Join \(A\) and \(C\). \(ABC\) is the required right-angled triangle