# Ex.2.3 Q5 fractions-and-decimals Solutions-Ncert Maths Class 7

## Question

Saili plants \(4\) saplings, in a row, in her garden. The distance between two adjacent saplings is \(\begin{align} \frac{3}{4}\rm\, m\end{align} \). Find the distance between the first and the last sapling.

## Text Solution

**What is known?**

Number of saplings and distance between two adjacent saplings.

**What is unknown?**

Distance between the first and the last sapling.

**Reasoning: **

Add the distance of first to second, second to third and third to fourth. Since all the sapling are plant equidistance to each other then we can simply multiply \(\begin{align}\frac{3}{4}\end{align}\)by \(3\).

**Steps:**

Total number of saplings \(\rm= 4\)

Distance between two adjacent saplings\(\begin{align} = \frac{3}{4}{\rm{m}}\end{align} \)

Distance between the first and the last sapling \(\begin{align}= 3 \times \frac{3}{4} = \frac{9}{4}{\rm{m}} = 2\frac{1}{4}{\rm{m}}\end{align} \)

Thus, the distance between the first and last sapling is \(\begin{align} 2\frac{1}{4}{\rm{m}}\end{align} \)