Ex.2.6 Q5 Linear Equations in One Variable Solutions-Ncert Maths Class 8

Solve:\(\begin{align} \frac{{7y + 4}}{{y + 2}} = \frac{{ - 4}}{3}\end{align}\)

Text Solution

What is known?

Equation

What is unknown?

Value of the variable

Reasoning:
Multiple both sides by the L.C.M of the denominators to get rid of fractional number. Now transpose variables to one side and constant to another side.

Steps:

On multiplying both sides by \(3(y + 2)\),we obtain

\[\begin{align}3\left( {7{\rm{ }}y + 4} \right) &=  - 4\left( {y + 2} \right)\\21y + 12 &=  - 4y - 8\\21y + 4y &=  - 8 - 12\\\,\,\,\,\,\,\,\,\,\,25y &=  - 20\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y &=  - \frac{4}{5}\end{align}\]