Ex.2.6 Q5 Linear Equations in One Variable Solutions-Ncert Maths Class 8

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Question

Solve:\begin{align} \frac{{7y + 4}}{{y + 2}} = \frac{{ - 4}}{3}\end{align}

Text Solution

What is known?

Equation

What is unknown?

Value of the variable

Reasoning:
Multiple both sides by the L.C.M of the denominators to get rid of fractional number. Now transpose variables to one side and constant to another side.

Steps:

On multiplying both sides by $$3(y + 2)$$,we obtain

\begin{align}3\left( {7{\rm{ }}y + 4} \right) &= - 4\left( {y + 2} \right)\\21y + 12 &= - 4y - 8\\21y + 4y &= - 8 - 12\\\,\,\,\,\,\,\,\,\,\,25y &= - 20\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y &= - \frac{4}{5}\end{align}

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