# Ex.2.6 Q5 Linear Equations in One Variable Solutions-Ncert Maths Class 8

Go back to 'Ex.2.6'

## Question

Solve:\(\begin{align} \frac{{7y + 4}}{{y + 2}} = \frac{{ - 4}}{3}\end{align}\)

Video Solution

Linear Equations

Ex 2.6 | Question 5

## Text Solution

**What is known?**

Equation

**What is unknown?**

Value of the variable

**Reasoning:**

Multiple both sides by the L.C.M of the denominators to get rid of fractional number. Now transpose variables to one side and constant to another side.

**Steps:**

On multiplying both sides by \(3(y + 2)\),we obtain

\[\begin{align}3\left( {7{\rm{ }}y + 4} \right) &= - 4\left( {y + 2} \right)\\21y + 12 &= - 4y - 8\\21y + 4y &= - 8 - 12\\\,\,\,\,\,\,\,\,\,\,25y &= - 20\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y &= - \frac{4}{5}\end{align}\]