# Ex.3.2 Q5 Understanding Quadrilaterals Solution - NCERT Maths Class 8

## Question

(a) Is it possible to have a regular polygon with measure of each exterior angle as \(22^\circ\)?

(b)Can it be an interior angle of a regular polygon? Why?

## Text Solution

**What is Known?**

Measure of an exterior angle is \(22^\circ\).

**What is Unknown?**

To find whether a regular polygon with exterior angle \(= 22^\circ\) is possible or not.

**Reasoning:**

Number of sides of any polygon

\[\begin{align}\,{\text{ }}&= \,\frac{{{\rm{36}}{{\rm{0}}^{\rm{\circ}}}}}{{{\text{Exterior angle}}}}\end{align}\]

where the answer is whole number .

**Steps:**

(a) Is it possible to have a regular polygon with measure of each exterior angle as \(22^\circ\)?

Total measure of all exterior angles \(= {\rm{36}}0^\circ \)

Let number of sides be \(= \rm n\). Measure of each exterior angle \(= {\rm{22}}^\circ \)

Therefore, the number of sides

\[\begin{align}&=\,\frac{{{\text{Sum of exterior angles}}}}{{{\text{Each exterior angle}}}}\\&= \frac{{{{360}^{\rm{o}}}}}{{{{22}^{\rm{o}}}}}\\&= 16.36\end{align}\]

We cannot have regular polygon with each exterior angle = \(22^\circ \) as the number of sides is not a whole number [ \(22\) is not a perfect divisor of \(360^\circ \)].

(b) Can it be an interior angle of a regular polygon? Why?

Measure of each interior angle \(= 22^\circ\)

Measure of each exterior angle

\[\begin{align}\\&= 180^\circ - {\rm{22}}^\circ {\rm{ }}\\&= {\rm{158}}^\circ\end{align}\]

Number of sides

\[\begin{align}&= \frac{{{\text{Sum of exterior angles}}}}{{{\text{Each exterior angle}}}}\\&= \frac{{{\rm{36}}0^\circ }}{{{\rm{158}}^\circ }}\\&= 2.27\end{align}\]

We cannot have regular polygon with each interior angle as \(22^\circ \) because the number of sides is not a whole number[ \(22\) is not a perfect divisor of \(360^\circ \)].