# Ex.6.3 Q5 Triangles Solution - NCERT Maths Class 10

Go back to  'Ex.6.3'

## Question

$$S$$ and $$T$$ are points on sides $$PR$$ and $$QR$$ of  $$\Delta PQR$$ such that  $$\angle P{\rm{ }} = \angle RTS$$. Show that

Diagram

## Text Solution

Reasoning:

If two angles of one triangle are respectively equal to two angles of another triangle, then the two triangles are similar.

This is referred as $$AA$$ criterion for two triangles.

Steps:

In $$\Delta RPQ,\,\,\Delta RTS$$

\begin{align}\angle R P Q&=\angle R T S \quad \text { (given) } \\ \angle P R Q&=\angle T R S \quad \text { (Commonangle) } \\ \Rightarrow\qquad \Delta R P Q &- \Delta R T S \quad \because \text { (AA criterion) }\end{align}

Learn math from the experts and clarify doubts instantly

• Instant doubt clearing (live one on one)
• Learn from India’s best math teachers
• Completely personalized curriculum