# Ex.6.5 Q5 Triangles Solution - NCERT Maths Class 10

Go back to 'Ex.6.5'

## Question

\(ABC\) is an isosceles triangle with \({AC = BC}\). If \(A B^{2}=2 A C^{2}\) prove that \(ABC\) is a right triangle.

**Diagram**

## Text Solution

**Reasoning:**

As we know ,In a triangle, if square of one side is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle.

**Steps:**

In \(\Delta A B C\)

\[AC = BC\]

And

\[\begin{align}A B^{2} &=2 A C^{2} \\ &=A C^{2}+A C^{2} \\ A B^{2} &=A C^{2}+B C^{2} \quad[\because A C=B C] \end{align}\]

\(\Rightarrow \angle A C B=90^\circ\)

\(\begin{align}\Rightarrow \Delta A B C \end{align}\) is a right triangle