# Ex.1.3 Q6 Integers Solution - NCERT Maths Class 7

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## Question

A certain freezing process requires that room temperature be lowered from $$40^\circ \rm C$$  at the rate of $$5^\circ{\rm C}$$  every hour. What will be the temperature $$10$$ hours after the process begins?

## Text Solution

Steps:

Present temperature of room $$=$$ $$40^\circ \rm C$$

Decrease in temperature after every hour $$= 5^\circ{\rm C}$$

Temperature of room after $$10$$ hours

\begin{align}&=40^{\circ} \mathrm{c}+10 \times(-5)^{\circ} \mathrm{c}\\&=40^{\circ} \mathrm{c}-50^{\circ} \mathrm{c}\\&=-10^{\circ} \mathrm{c}\end{align}

Thus, the room temperature after $$10$$ hours is $$–10^\circ{\rm C},$$ after the process begins.

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