# Ex 13.1 Q6 Exponents and Powers Solution- NCERT Maths Class 7

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## Question

Simplify:

(i)  $$2\times {{10}^{3}}$$

(ii) $${{7}^{2}}\times {{2}^{2}}$$

(iii) $${{2}^{3}}\times 5$$

(iv) $$3\times {{4}^{4}}$$

(v) $$0\times {{10}^{2}}$$

(vi) $${{5}^{2}}\times {{3}^{3}}$$

(vii) $${{2}^{4}}\times {{3}^{2}}$$

(viii)  $${{3}^{2}}\times {{10}^{4}}$$

Video Solution
Exponents And Powers
Ex 13.1 | Question 6

## Text Solution

What is known?

Base and exponent.

What is unknown?

Simple form of the number.

Reasoning:.

In this question we will multiply the base and the number of times it’s exponent to simplify the given statement.

(i)

\begin{align} 2\times {{10}^{3}}&=2\times (10\times 10\times 10)\\&=2\times 1000\\&=2000\end{align}

(ii)

\begin{align} {{7}^{2}}\times {{2}^{2}}&=(7\times 7)\times (2\times 2)\\&=49\times 4\\&=196\end{align}

(iii)

\begin{align}{{2}^{3}}\times 5&=(2\times 2\times 2)\times 5\\&=8\times 5\\&=40\end{align}

(iv)

\begin{align}3\times {{4}^{4}}&=3\times (4\times 4\times 4\times 4)\\&=3\times 256\\&=768\end{align}

(v)

\begin{align}0\times {{10}^{2}}&=0\times 10\times 10\\&=0\end{align}

(vi)

\begin{align}{{5}^{2}}\times {{3}^{3}}&=(5\times 5)\times (3\times 3\times 3)\\&=25\times 27\\&=675\end{align}

(vii)

\begin{align}{{2}^{4}}\!\times \!{{3}^{2}}&=(\!2\times\!\! 2\times \!2\times\!2)\!\times \!(3\!\times\!3)\\&=16\!\times\! 9\\&=144\end{align}

(viii)

\begin{align}{3^2}\!\! \times\!\! {10^4}&=\!\! (3\!\!\times\!\!3)\!\!\times\!\!(10\!\!\times\!\!10\!\!\times\!\!10\!\!\times\!\!10) \\&= 9\!\times\!10000 \\&= 90000\end{align}

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