In the verge of coronavirus pandemic, we are providing FREE access to our entire Online Curriculum to ensure Learning Doesn't STOP!

# Ex.13.6 Q6 Surface Areas and Volumes Solution - NCERT Maths Class 9

Go back to  'Ex.13.6'

## Question

The capacity of a closed cylindrical vessel of height $$1 \; \rm m$$ is $$15.4$$ litres. How many square metres of metal sheet would be needed to make it?

Video Solution
Surface-Areas-And-Volumes
Ex exercise-13-6 | Question 6

## Text Solution

Reasoning:

Surface area total of a closed cylinder is $$2\pi rh + 2\pi {r^2}$$.

$$2\pi rh$$ corresponds to the Curved Surface Area of the cylinder and  $$2\pi {r^2}$$ corresponds to the area of the circular lids of the cylindrical vessel in order to make it a closed container. Volume of cylinder $$\pi {r^2}h$$.

What is known?

Capacity and height of the cylinder.

What is unknown?

Metal sheet needed to make it.

Steps:

\begin{align}\text{Capacity} &= \rm{15.4 \, liters}\\ V &= \frac{{15.4}}{{1000}} = .0154\,\,\rm {m^3} \end{align}

\begin{align}\rm{Volume} &= \pi {r^2}h\\ 0.0154 &= \frac{{22}}{7} \times {r^2} \times 1 \\{r^2} &= \frac{{.0154 \times 7}}{{22}}\\{r^2} &= .0049\\r &= \sqrt {.0049} \\ &= 0.07\,\, \rm m \end{align}

Curved surface area

\begin{align} & = 2\pi rh + 2\pi {r^2} \\ & = 2\pi r(r + h) \\ & = 2 \times \frac{{22}}{7} \times 0.07 \times (0.07 + 1) \\ & = 0.4708\,\, \rm {m^2} \end{align}

$$0.47\, \rm {m^2}$$ of metal sheet would be needed.