# Ex.5.3 Q6 Data Handling Solutions - NCERT Maths Class 8

## Question

Find the probability of the events given in Question \(2.\)

## Text Solution

**What is known?**

A situation in which a die is thrown.

**What is unknown?**

Probability of the events

**Reasoning:**

Probability

\(\begin{align} =\frac{{{\text{Number of favourable outcomes}}}}{{{\text{Total number of outcomes}}}} \end{align}\)

**Steps:**

When a die is thrown, there are total six outcomes, i.e., \(1, 2, 3, 4, 5\) and \(6.\)

(i) (a) \(2, 3, 5\) are prime numbers. So, there are \(3\) outcomes out of \(6.\)

Therefore,probability of getting a prime number

\(\begin{align} = \frac{3}{6} = \frac{1}{2} \end{align}\)

(b) \(1, 4, 6\) are not the prime numbers. So, there are \(3\) outcomes out of \(6.\)

Therefore, probability of getting a prime number

\(\begin{align} = \frac{3}{6} = \frac{1}{2} \end{align}\)

(ii) (a) Only \(6\) is greater than \(5.\) So, there is one outcome out of \(6.\)

Therefore, probability of getting a number greater than

\(\begin{align} 5 = \frac{1}{6} \end{align}\)

(b) Numbers not greater than \(5\) are \(1, 2, 3, 4\) and \(5.\) So there are \(5\) outcomes out of \(6.\)

Therefore, probability of not getting a number greater than

\(\begin{align} 5 = \frac{1}{6} \end{align}\)